Find the remainder obtained when t6+3t2+10 is divided by t3+1.
A
t2−11
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B
t3−1
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C
3t2+11
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D
None
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Solution
The correct option is C3t2+11 We divide the polynomial t6+3t2+10 by t3+1 as shown in the above image and we observe that the quotient is t3−1 and the remainder is 3t2+11.