Question

Find the remainder of $f\left(x\right)=x^2-3x+2$ when $f\left(x\right)$ is divided by $(x-3)$.

Answer 1

Given, $f\left(x\right)=x^2-3x+2$.

Now according to the remainder theorem, when $f\left(x\right)$ is divided by $(x-3)$ then the remainder obtained is $f\left(3\right)$.

Then,

$f\left(3\right)=(3{)}^2-3(3)+2$

$f\left(3\right)=9-9+2=2$.

Therefore, the required remainder is $2$.