Question

Find the remainder using remainder theorem, when:

$3x^3+4x^2-5x+8$ is divided by $x-1$

Answer 1

According to remainder theorem, when $f\left(x\right)$ is divided by $(x-1)$, Remainder $=f\left(1\right)$

$f\left(x\right)=3x^3+4x^2-5x+8$

$f\left(1\right)=3(1{)}^3+4(1{)}^2-5\left(1\right)+8$

$=3+4-5+8=10$

$\therefore$ Remainder$=10$