Question

Find the remainder using remainder theorem, when:

$4x^3-3x^2+2x-4$ is divided by $x+3$

Answer 1

According to remainder theorem when $f\left(x\right)$ is divided by $(x+3)$, Remainder $=f(-3)$

$f\left(x\right)=4x^3-3x^2+2x-4$

$f(-3)=4(-3{)}^3-3(-3{)}^2+2(-3)-4$

$=4\times -27-3\times 9-6-4=-108-27-10=-145$

$\therefore$ Remainder $=-145$