Question

Find the remainder using remainder theorem, when:

$x^3-a{x}^2-5x+2a$ is divided by $x-a$

Answer 1

According to remainder theorem, when $f\left(x\right)$ is divided by $(x-a)$, Remainder $=f\left(a\right)$

$f\left(x\right)=x^3-a{x}^2-5x+2a$

$f\left(a\right)=a^3-a(a{)}^2-5(a)+2a$

$=a^3-a^3-5a+2a$

$-3a$

$\therefore$ Remanider$=-3a$