We can apply Euler's Remainder Theorem here as 10 and 7 are co-primes.
Euler's number of 7 (a prime number) is 7−1=6. Make the numerator power the nearest multiple of 6.
The question changes to - 10996×104 divided by 7.
10996 = 10166×6 will leave a remainder of 1 when divided by 7.
104 when divided by 7 leaves a remainder of 4.
So, actual remainder will be 1×4 = 4.