Question

Find the remainder when $30y^4+11y^3-42y^2+24y+3$ is divided by is divided by $3y^2+2y$ ?

• A. 2y+3
• B. 3
• C. y-2

Answer 1

The correct option is B 3

$\frac{30y^4+11y^3-42y^2+24y+3}{3y^2+2y}$
$\stackrel{10y^2-3y-12}{\sqrt[3y^2+2y]{3y^2+2y30y^4+11y^3-42y^2+24y+3}}30y^4+20y^3--\underset{–}{}-9y^3-42y^2-9y^3-6y^2++\underset{–}{}-36y^2+24y-36y^2-24y-\underset{–}{}3\underset{–}{}$
$\therefore$ Remainder when $30y^4+11y^3-42y^2+24y+3$ is divided $3y^2+2y$ is 3.