Find the remainder when $4 t^{3} + 2 t^{2} + 3$ is divided by (t + 1).
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Solution

The correct option is A 1
$\begin{matrix} 4 t^{2} - 2 t + 2 (t + 1) 4 t^{3} + 2 t^{2} + 3 ‘ 4 t^{3} + 4 t^{2} - - - -------------- - - 2 t^{2} + 3 - 2 t^{2} - 2 t + + - ----------------------- - 2 t + 3 2 t + 2 - - - ----- - 1 - --- - \end{matrix}$

So, remainder is 1.

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