Question

Find the remainder when $9^{400}+9^{401}+9^{402}.......9^{410}$ is divided by 6?

• A. 1
• B. 3
• C. 2

Answer 1

The correct option is B 3

Any power of 9 when divided by 6, gives a remainder 3. hence answer $=\frac{11\times 3}{6}$((As there are $11$ terms)= $\frac{33}{6}$ = Remainder $=3$