Find the remainder when p(x) = 3x2+x+−1 is divided by g(x) = 1 + x.
+1
Method 1:
3x−2x+13x2+x−1 3x2+3x––––––––––2 −2x−1 −2x−2––––––––– 1
Method 2:
Here p(x)=3x2+x−1
The zero of g(x)=x+1 is −1
p(−1)=3x(−1)2+(−1)−1=3−1−1=1
So by the remainder theorem, 1 is the remainder.