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Question

Find the remainder when p(x) = 3x2+x+−1 is divided by g(x) = 1 + x.


A

2

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B

3

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C

-1

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D

+1

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Solution

The correct option is D

+1


Method 1:

3x2x+13x2+x1 3x2+3x––––––––2 2x1 2x2––––––– 1

Method 2:
Here p(x)=3x2+x1
The zero of g(x)=x+1 is 1
p(1)=3x(1)2+(1)1=311=1
So by the remainder theorem, 1 is the remainder.


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