You visited us 1 times! Enjoying our articles? Unlock Full Access!

Factor Theorem

Find the rema...

Question

Find the remainder when : $p (x) = 3 x^{3} - 4 x^{2} + 7 x + 5$ is divided by $(x - 3)$ and $(x + 3)$

Open in App

Solution

$p (x) = 3 x^{3} - 4 x^{2} + 7 x + 5$
According to remainder theorm, $p (3) a n d p (- 3)$ will give us the remainder
$p (3) = 3 (3)^{3} - 4 (3)^{2} + 7 (3) + 5$
$= 81 - 36 + 21 + 5 = 71$

$p (- 3) = 3 (- 3)^{3} - 4 (- 3)^{2} + 7 (- 3) + 5$
$= - 81 - 36 - 21 + 5 = - 133$

Suggest Corrections

Similar questions

p (x) = - 3 x^{3} - 4 x^{2} + 10 x - 7

x - 2

(7 x^{2} + x + 5)

(3 x^{3} - 2 x^{2} + 7 x - 5) \div (x + 3)

p (x) = a x^{3} + 4 x^{2} + 3 x - 4

q (x) = x^{3} - 4 x + a

(x - 3)

a

p (x)

(x - 2) .

p (x) = 2 x^{4} - 3 x^{3} - 5 x^{2} + 8 x - 3

p (x)

(x - \frac{3}{2})

3 x^{3} - 7 x + 7

x + 2

Join BYJU'S Learning Program