Question

Find the remainder when $p\left(x\right)=x^3+3x^2+3x+1$, is divided by $x$

• A. 1
• B. 0
• C. -1
• D. 3

Answer 1

The correct option is A 1

Here, $p\left(x\right)=x^3+3x^2+3x+1$, and the zero of $x$ is $0$
So, $p\left(0\right)=(0{)}^3+3\times (0{)}^2+3\left(0\right)+1$
$=0+0+0+1=1$
So, by the Remainder Theorem, $1$ is the remainder when $x^3+3x^2+3x+1$ is divided by $x$.