Find the remainder when the polynomial $4 x^{3} + 12 x^{2} + 11 x + 3$ is divided by $x + 1$

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Solution

The correct option is A
0

Substitute x = -1 in the polynomial we will get the remainder.

$4 (- 1)^{3} + 12 (- 1)^{2} + 11 (- 1) + 3 = - 4 + 12 - 11 + 3 = 15 - 15 = 0$

Remainder = 0

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