Find the remainder when we divide $(9 x^{4} + 3 x^{3} y + 16 x^{2} y^{2} + 24 x y^{3} + 32 y^{4})$ by $(3 x^{2} + 5 x y + 4 y^{2})$

Open in App

Solution

We divide $9 x^{4} + 3 x^{3} y + 16 x^{2} y^{2} + 24 x y^{3} + 32 y^{4}$ by $3 x^{2} + 5 x y + 4 y^{2}$ as shown in the above image:

From the above division, we get that the quotient is $3 x^{2} - 4 x y + 8 y^{2}$ and the remainder is $0$

Hence, the remainder is $0$ .

Suggest Corrections

Similar questions

9 x^{4} + 3 x^{3} y + 16 x^{2} y^{2} + 24 x y^{3} + 32 y^{4}

(3 x^{2} + 5 x y + 4 y^{2})

(3 x^{2} + 5 x y + 4 y^{2})

9 x^{4} + 3 x^{3} y + 16 x^{2} y^{2} + 24 x y^{3} + 32 y^{4}

(9 x^{4} + 3 x^{3} y + 16 x^{2} y^{2}) + 24 x y^{3} + 32 y^{4}

(3 x^{2} + 5 x y + 4 y^{2})

3 x^{2} - 4 x y + 8 y^{2}

x^{7} y - x y^{7}

(x + y) (x^{2} - x y + y^{2})

Join BYJU'S Learning Program