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Question

Find the remainder when x100 is divided by x23x+2

A
(21001)x+(21001)
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B
(21001)x+(11002)
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C
(21001)x+(22100)
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D
(21002)x+(22100)
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Solution

The correct option is C (21001)x+(22100)
x100=p(x)(xz)(x1)+(ax+b)
x=1 1100=a+b a+b=1
x=2 2100=0+2a+b a=21001 b=22100
R(x)=(21001)x+(22100)


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