Find the remainder when $x^{3} + 2 x^{2} + 4 x + 3$ is divided by the polynomial $x - 1$

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Solution

The remainder when a polynomial $p (x)$ is divided by $(x - a)$ is given by $p (a)$ .
Therefore, remainder is: $1^{3} + 2 \cdot 1^{2} + 4 \cdot 1 + 3 = 1 + 2 + 4 + 3 = 10$

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Similar questions

Q. Find the remainder when

x^{4} + x^{3} - 2 x^{2} + x + 1

is divided by

x - 1

Q. By using the remainder theorem, divide the polynomial

x^{3} - 2 x^{2} - 4 x - 1

x - 1

and find the remainder.

Q. By Remainder Theorem find the remainder, when

p (x)

is divided by

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, where

p (x) = x^{3} - 2 x^{2} - 4 x - 1

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Q. Find the remainder polynomial when the cubic polynomial

x^{3} - 3 x^{2} + 4 x + 5

is divided by

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When the polynomial $x^{3} + 2 x^{2} - 5 a x - 7$ is divided by $(x - 1)$ , the remainder is A and when the polynomial $x^{3} + a x^{2} - 12 x + 16$ is divided by $(x + 2)$ , the remainder is B. Find the value of 'a' if $2 A + B = 0$ .

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Find the remainder when x3+2x2+4x+3 is divided by the polynomial x−1

The remainder when a polynomial p(x) is divided by (x−a) is given by p(a).Therefore, remainder is: 13+2⋅12+4⋅1+3=1+2+4+3=10

Find the remainder when $x^{3} + 2 x^{2} + 4 x + 3$ is divided by the polynomial $x - 1$

The remainder when a polynomial $p (x)$ is divided by $(x - a)$ is given by $p (a)$ .
Therefore, remainder is: $1^{3} + 2 \cdot 1^{2} + 4 \cdot 1 + 3 = 1 + 2 + 4 + 3 = 10$