Find the remainder when $x^{3} + 4 x^{2}$ + 4x -3 is divided by x.

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Solution

f(x) = $x^{3} + 4 x^{2}$ + 4x - 3

Dividing f(x) by x, we get

Let x = 0, then f(0) + 0 + 0 -3=-3

$∴$ Remainder =-3

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