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Byju's Answer
Standard IX
Mathematics
Remainder Theorem
Find the rema...
Question
Find the remainder when
x
3
−
6
x
2
+
2
x
−
4
is dividend by
3
x
−
1
.
Open in App
Solution
Let
f
(
x
)
=
x
3
−
6
x
2
+
2
x
−
4
.
The polynomial
f
(
x
)
is divided by
3
x
−
1
.
Then
3
x
−
1
=
0
⟹
3
x
=
1
⟹
x
=
1
3
.
By remainder theorem, the remainder is given by
f
(
1
3
)
.
Hence, remainder of the given polynomial
f
(
x
)
is :
f
(
1
3
)
=
(
1
3
)
3
−
6
(
1
3
)
2
+
2
(
1
3
)
−
4
=
(
1
3
)
3
−
6
(
1
3
)
2
+
2
(
1
3
)
−
4
=
(
1
27
)
−
6
(
1
9
)
+
2
(
1
3
)
−
4
=
(
1
27
)
−
(
6
9
)
+
(
2
3
)
−
4
=
1
−
(
6
×
3
)
+
(
2
×
9
)
−
(
4
×
27
)
27
=
1
−
18
+
18
−
108
27
=
−
107
27
.
That is, the remainder obtained is
−
107
27
.
Suggest Corrections
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Similar questions
Q.
Find the remainder when
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x
)
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x
3
−
6
x
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Find the remainder when
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By Remainder Theorem find the remainder, when
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p
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x
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Q.
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