Question

Find the remaining numbers of the Pythagorean triplet whose smallest number is 24.

• A. 133, 135
• B. 153, 155
• C. 143, 145
• D. 123, 125

Answer 1

The correct option is C 143, 145

There are three numbers $2m,m^2-1and{m}^2+1,$ in a Pythagorean Triplet $(for,m>1)$.

$Here,2m=24\Rightarrow m=\frac{24}{2}=12\therefore \text{Second number}(m^2-1)=(12{)}^2-1=144-1=143\text{And third number}(m^2+1)=(12{)}^2+1=144+1=145$

Hence, the Pythagorean triplet is (24, 143, 145) and the correct option is B.