Question

Find the resistance across points $A$ and $B$.

• A. $\frac{2}{3}\Omega$
• B. $\frac{4}{3}\Omega$
• C. $3\Omega$
• D. $\frac{3}{4}\Omega$

Answer 1

The correct option is B $\frac{4}{3}\Omega$

Here, the vertices of traingle $ABC$ are connected directly to the vertices of the traingle $DEF$.
Therefore, points $A,B,C$ are at the same potential as the points $D,E,F$ respectively.

Hence, the above circuit can be redrawn as :

The above circuit can be simplified as :
Hence, the net resistance between points $A$ and $B$ is given by :
$R_{AB}=\frac{4\times 2}{4+2}=\frac{4}{3}\Omega$