Question

Find the resistor in which maximum heat will be produced. (in $\Omega$)

Answer 1

Above circuit is equivalent to to parallel combinations of resistors of $5\Omega ,6\Omega ,2\Omega$ ;and $5\Omega ,4\Omega$.
Voltage across first parallel combination = $V\frac{15/13}{15/13+20/9}=\frac{27}{79}V$
Voltage across second parallel combination = $V\frac{20/9}{15/13+20/9}=\frac{52}{79}V$
heat in resistors of first parallel combination are $\frac{{27}^2{V}^2}{{79}^{2}5},\frac{{27}^2{V}^2}{{79}^{2}6},\frac{{27}^2{V}^2}{{79}^{2}2}$ in the resistors $5\Omega ,6\Omega ,2\Omega$ respectively.
heat in resistors of second parallel combination are $\frac{{52}^2{V}^2}{{79}^{2}5},\frac{{52}^2{V}^2}{{79}^{2}4}$ in the resistors $5\Omega and4\Omega$ respectively.
maximum heat is produced in resistor of $4\Omega$