10 g of ice at $0^{o} C$ absorbs 5460 J of heat energy to melt and change to water at $50^{o} C$ . Calculate the specific latent heat of fusion of ice. Specific heat capacity of water is 4200 J $k g^{-} 1 K^{- 1}$ .

Q. A refrigerator converts

100 g

of water at

20^{o} C

to ice at -

10^{o} C

73.5 m i n

. Calculate the average rate of heat extraction in Watt. The specific heat capacity of water is

4.2 J g^{- 1} K^{- 1}

, specific latent heat of ice is

336 J g^{- 1}

and the specific heat capacity of ice is

2.1 J g^{- 1} K^{- 1}

10 g of ice at 0 $^{\circ} C$ absorbs 5460 J of heat energy to melt and change t water at 50 $^{\circ} C$ . Calculate the specific latent heat of fusion of ice. (Specific heat capacity of water is 4200 J $K g^{- 1} K^{- 1}$ .

Q. A piece of ice of mass

40 g

0^{o} C

is added to

200 g

of water at

50^{\circ} C

. Calculate the final temperature of water when all the ice has melted. Specific heat capacity of water =

4200 J k g^{- 1} K^{- 1}

and specific latent heat of fusion of ice =

336 \times 10^{3} J k g^{- 1}

Join BYJU'S Learning Program

Find the result of mixing 10 g of ice at −10oC with 10 g of water at 10oC. Specific heat capacity of ice =2.1 Jg−1K−1, specific latent heat of ice =336 Jg−1 and specific heat capacity of water =4.2 Jg−1K−1

The correct option is A 0.625 g ice will melt. Temperature will remain 0oCheat require to bring water at 0oC Q1=10×4.2×10=420Jheat released by ice when it reaches 0oQ2=10×2.1×10=210Jamount of ice melt is mQ1−Q2=mLm=0.625g and final temperature is 0oC

Find the result of mixing $10 g$ of ice at $- 10^{o} C$ with $10 g$ of water at $10^{o} C$ . Specific heat capacity of ice $= 2.1 J g^{- 1} K^{- 1}$ , specific latent heat of ice $= 336 J g^{- 1}$ and specific heat capacity of water $= 4.2 J g^{- 1} K^{- 1}$