Question

Find the rise in temperature of a copper vessel of mass $200g$, when$1600calories$ of heat is supplied to it. Specific heat of cooper $=420Jk{g}^{-1}°C^{-1}.$

Answer 1

Step 1: Given data

Mass of copper vessel,

$$\begin{gathered} m=200g \\ =200\times {10}^{-3}kg \\ =0.2kg \end{gathered}$$

Heat supplied ,

$$\begin{gathered} Q=1600calories \\ =1600\times 4.184J(1cal=4.184J) \end{gathered}$$

Specific heat of copper $c=420Jk{g}^{-1}°C^{-1}$

Step 2. Finding rise in temperature

Rise in temperature, $△t=?$

Heat supplied is given as,

$Q=mc△t$,

So,

$△t=\frac{Q}{mc}$

$=\frac{1600\times 4.184J}{0.2kg\times 420Jk{g}^{-1}°C^{-1}}$

$$\begin{gathered} =\frac{6694.4}{84} \\ =79.695 \\ \mathbf{\approx }\mathbf{}\mathbf{80}\mathbf{}\mathbf{°}\mathit{C} \end{gathered}$$

Hence, temperature of the copper vessel rises by $80°C$.