Question

Find the root of the equation $16x-\frac{10}{x}-27$

Answer 1

$16x-\frac{10}{x}-27=0$

$16x^2-10-27x=0$

$16x^2-27x-10=0$

$16x^2-32x+5x-10=0$

$(x-2)(16x+5)=0$

$x=2,-\frac{5}{16}$

Hence the roots of the equation are $2,-\frac{5}{16}$.