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Question

Find the root of the perpendicular from point (2,3,2) to the line 4x2=y6=1z3 also find perpendicular distance from the point to the line.

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Solution

4x2=y6=1z3x42=y6=z13FromthefigureA(2,3,2)B(2r+4,6r,3r+1)DirectionratioofAB=(2r+2,6r3,3r1)dot product of drs of AB and line = 02(2r+2)+6(6r3)3(3r1)=049r=19r=1949Footofperpendicular=(3849+4,11449,5749+1)=(15849,11449,1249)Perpendiculardistance=(158492)2+(114493)2+(12492)2=3600+1089+12149=16,78949


1235804_1301981_ans_1dafda6613c746ec9e11d5732fab0195.PNG

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