Find the roots of $2 m^{2} + 19 m + 30 = 0$
A) $- 2, \frac{15}{2}$
B) $2, \frac{15}{2}$
C) $2, \frac{- 15}{2}$

D) $- 2, \frac{- 15}{2}$

2, \frac{15}{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

- 2, \frac{15}{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2, \frac{- 15}{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

- 2, \frac{- 15}{2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D: $- 2, \frac{- 15}{2}$
The given quadratic equation is : $2 m^{2} + 19 m + 30 = 0$
$\Rightarrow 2 m^{2} + (15 + 4) m + 30 = 0$ [on factorisation]
$\Rightarrow 2 m^{2} + 15 m + 4 m + 30 = 0$
$\Rightarrow m (2 m + 15) + 2 (2 m + 15) = 0$
$\Rightarrow (m + 2) (2 m + 15) = 0$
$\Rightarrow (m + 2) = 0 o r, (2 m + 15) = 0$
$\Rightarrow m = - 2, m = \frac{- 15}{2}$
Thus, the roots of the quadratic equation are $- 2, \frac{- 15}{2}$

Suggest Corrections

Similar questions

The coefficient of $x$ in the equation $a x^{2} + b x + c = 0$ was wrongly taken as $17$ instead of $13$ & its roots were $- 2, - 15$ . Actual roots are _____.

Q. For what value of

m

, the points

(3, 5)

(m, 6)

and

(\begin{matrix} \frac{1}{2}, \frac{15}{2} \end{matrix})

are collinear?

Q. 2m² + 19m + 30 = 0

Q. If p, q are the roots of the equation

x^{2} - 3 x + 2 = 0

, find the equation which has roots as (2p + 1) and (2q + 1).

x^{2} + 2 x + 2 = 0

has the roots as

α

and

β

then find

α^{15} + β^{15} = ?

Join BYJU'S Learning Program

Find the roots of 2m2+19m+30=0A) −2,152B) 2,152C) 2,−152D) −2,−152

The correct option is D: −2,−152The given quadratic equation is : 2m2+19m+30=0⇒2m2+(15+4)m+30=0 [on factorisation]⇒2m2+15m+4m+30=0⇒m(2m+15)+2(2m+15)=0⇒(m+2)(2m+15)=0⇒(m+2)=0or,(2m+15)=0⇒m=−2,m=−152Thus, the roots of the quadratic equation are −2,−152

Find the roots of $2 m^{2} + 19 m + 30 = 0$
A) $- 2, \frac{15}{2}$
B) $2, \frac{15}{2}$
C) $2, \frac{- 15}{2}$

D) $- 2, \frac{- 15}{2}$