Find the roots of $3 x^{2} - 11 x + 6 = 0$

3, \frac{2}{3}

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3, \frac{- 2}{3}

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- 3, \frac{2}{3}

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- 3, \frac{- 2}{3}

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Solution

The correct option is A $3, \frac{2}{3}$
$3 x^{2} - 11 x + 6 = 0$
$∴ 3 x^{2} - 9 x - 2 x + 6 = 0$
$∴ 3 x (x - 3) - 2 (x - 3) = 0$
$∴ (3 x - 2) (x - 3) = 0$
$∴ x = 3$ and $x = \frac{2}{3}$

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