wiz-icon
MyQuestionIcon
MyQuestionIcon
2
You visited us 2 times! Enjoying our articles? Unlock Full Access!
Question

Find the roots of each of the following equations, if they exist, by applying the quadratic formula:
x2+6x(a2+2a8)=0

Open in App
Solution

x2+6x(a2+2a8)=0
Solving the Q.E in x,we have

x=b±b24ac2

Discriminant, D=b24ac

D=624((a2+2a8))

=36+4a2+8a32=36+4a2+8a32=4a2+8a+4=4(a+1)2>0,so solution exists

x=b±D2

x=6±4(a+1)22

x=6±2(a+1)2

x=3+a+1 or x=3a1

x=a2 or x=a4


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Solving QE Using Quadratic Formula
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon