Find the roots of equation
$p q x^{2} + (q^{2} - p r) x - q r = 0$

- \frac{r}{q}, \frac{q}{p}

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\frac{- p}{q}, \frac{r}{q}

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\frac{- q}{p}, \frac{r}{q}

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\frac{- p}{q}, \frac{q}{r}

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Solution

The correct option is C $\frac{- q}{p}, \frac{r}{q}$
$p q x^{2} + (q^{2} - p r) x - q r = 0$
$p q x^{2} + q^{2} x - p r x - q r = 0$
$q x (p x + q) - r (p x + q) = 0$
$(p x + q) (q x - r) = 0$
$x = \frac{- q}{p}, x = \frac{r}{q}$

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Find the roots of equationpqx2+(q2−pr)x−qr=0

The correct option is C −qp,rqpqx2+(q2−pr)x−qr=0pqx2+q2x−prx−qr=0qx(px+q)−r(px+q)=0(px+q)(qx−r)=0x=−qp,x=rq

Find the roots of equation
$p q x^{2} + (q^{2} - p r) x - q r = 0$

The correct option is C $\frac{- q}{p}, \frac{r}{q}$
$p q x^{2} + (q^{2} - p r) x - q r = 0$
$p q x^{2} + q^{2} x - p r x - q r = 0$
$q x (p x + q) - r (p x + q) = 0$
$(p x + q) (q x - r) = 0$
$x = \frac{- q}{p}, x = \frac{r}{q}$