Question

Find the roots of equation:
$x^2-\frac{1}{12}x-\frac{1}{12}=0$

• A. $\frac{-1}{4},\frac{1}{3}$
• B. $4,3$
• C. $\frac{-1}{4},\frac{-1}{3}$
• D. $-4,-3$

Answer 1

The correct option is A $\frac{-1}{4},\frac{1}{3}$

We have, $x^2-\frac{1}{12}x-\frac{1}{12}=0$

$\Rightarrow$ $x^2+\frac{1}{4}x\times \frac{1}{3}x-\frac{1}{12}=0$

$\Rightarrow$ $x(x+\frac{1}{4})-\frac{1}{3}(x+\frac{1}{4})=0$

$\Rightarrow$ $(x+\frac{1}{4})(x-\frac{1}{3})=0$

$\Rightarrow$ $x=\frac{-1}{4}orx=\frac{1}{3}$