Question

Find the roots of fraction $\frac{x}{(x+3)(x-4)}=1$

Answer 1

$\begin{array}{c}Wehave\\ x=\left(x+3\right)\left(x-4\right)\\ \Rightarrow x=x^2+3x-4x-12\\ \Rightarrow x^2-2x-12=0\\ u\sin gformula\\ x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\ x=\frac{2\pm \sqrt{4+48}}{2}\\ =\frac{2\pm 2\sqrt{13}}{2}\\ =1\pm \sqrt{13}\\ Hence,\\ Rootsofquadraticare1+\sqrt{13}and1-\sqrt{13}.\end{array}$