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Question

Find the roots of quadratic equation 2x2+7x+52=0

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Solution

Given,
2x2+7x+52=0
or, 2x2+2x+5x+52=0
or, x2(x+2)+5(x+2)=0
or, (x2+5)(x+2)=0
x=52,2.
These are the required roots.

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