Find the roots of quadratic equation using factorization: $y^{2} - 2 y - 8 = 0$

- 2, 4

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- 4, 2

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2, 4

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None

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Solution

The correct option is D $- 2, 4$

$y^{2} - 2 y - 8 = 0, y^{2} - 4 y + 2 y - 8 = 0$
$(y - 4) (y + 2) = 0, y = 4, y = - 2$

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