Find the roots of quadratic equations.
$x^{2} + 10 x + 24 = 0$

- 6, 4

No worries! We‘ve got your back. Try BYJU‘S free classes today!

6, - 4

No worries! We‘ve got your back. Try BYJU‘S free classes today!

6, 4

No worries! We‘ve got your back. Try BYJU‘S free classes today!

- 6, - 4

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is C $- 6, - 4$
Given equation is
$x^{2} + 10 x + 24 = 0$
$x^{2} + 6 x + 4 x + 24 = 0$
$(x + 6) (x + 4) = 0$
$∴ x = - 4, - 6$
$∴$ roots of the given equation are $- 4, - 6$

Suggest Corrections

Similar questions

x^{2} - 4 = 0 a n d x^{2} - 5 x + 6 = 0

x^{2} - 10 x + 24 = 0

x^{2} - 4

x^{2} - 5 x + 6

6 x^{2} - 13 x + 6 = 0

\sqrt{6} x^{2} - 5 x + \sqrt{6} = 0

24 x^{2} - 17 x + 3 = 0

x^{2} + 2 x + 4 = 0

x^{2} + x + 1 = 0

x^{2} - 3 \sqrt{3} x - 30 = 0

x^{2} - 5 x + 6 = 0

Join BYJU'S Learning Program