Question

Find the roots of the equation $2x^2–5x+3=0$, by factorisation method.

• A. -$\frac{5}{2}$, $\frac{3}{2}$
• B. $4,2$
• C. $\frac{3}{2},1$
• D. -$\frac{3}{2},1$

Answer 1

The correct option is C

$\frac{3}{2},1$

Given equation: $2x^2–5x+3=0$

We need to find two numbers whose product is 6 and whose sum is -5.

We see that product of -2 and -3 is 6 and sum is -5. So, lets use these numbers.

So, $2x^2–5x+3=0$

$\Rightarrow 2x^2–2x–3x+3=0$

$\Rightarrow 2x(x–1)–3(x–1)=0$

$\Rightarrow (2x–3)(x–1)=0$

$\Rightarrow 2x–3=0orx–1=0$

$\Rightarrow x=\frac{3}{2}$ or $x=1$

$\therefore \frac{3}{2}$ and 1 are the roots of the quadratic equation $2x^2–5x+3=0$.