Find the roots of the equation $2 x^{2} - 7 x - 39 = 0$ by the method of factorization.

$x = \frac{13}{2}, x = - 3$

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$x = \frac{13}{5}, x = - 5$

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$x = 3$

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$x = 5$

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Solution

The correct option is A
$x = \frac{13}{2}, x = - 3$

$2 x^{2} - 7 x - 39 = 0$ [ Expressing as $a x^{2} + b x + c = 0$ ]
Now, by using the method of factorization
$\to$ $2 x^{2} - 13 x + 6 x - 39 = 0$
$x (2 x - 13) + 3 (2 x - 13) = 0$
$(2 x - 13) (x + 3) = 0$
$2 x - 13 = 0, o r x + 3 = 0$
$\to$ $x = \frac{13}{2}, o r x = - 3$

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Find the roots of the quadratic equation $\sqrt{2} x^{2} + 7 x + 5 \sqrt{2} = 0$ using factorisation method.

Find the roots of the equation $2 x^{2} - 7 x - 39 = 0$ by the method of factorization.

\sqrt{2} x^{2} + 7 x + 5 \sqrt{2} = 0

2 x^{2} - 7 x + 3 = 0

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