Question

Find the roots of the equation by the method of Completion of Squares:
$x^2-6x+9=0$

• A. $3,3$
• B. $-3,-3$
• C. $2,2$
• D. $-1,-1$

Answer 1

The correct option is A $3,3$

$x^2-6x+9=0$

$x^2-2\ast 3\ast x+3^2=0$

$(x-3{)}^2=0$

$(x-3)(x-3)=0$

Roots are $3,3$.