Find the roots of the equation:
$2 y^{2} - 6 y - 20 = 0$

2, 5

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- 2, 5

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- 2, - 5

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Solution

The correct option is A $- 2, 5$
$2 y^{2} - 6 y - 20 = 0$
$2 [y^{2} - 3 y - 10] = 0$
$y^{2} - 5 y + 2 y - 10 = 0, (y + 2) (y - 5) = 0$
$y = - 2, y = 5$

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