Question

Find the roots of the equation in $3x^2-4x+5=0$.

Answer 1

$3x^2-4x+5=0$

$x=\frac{-b\sqrt{b^2-4ac}}{2a}$

$a=3,b=-4,c=5$

$x=\frac{4\sqrt{4^2-4\left(3\right)\left(5\right)}}{2\left(3\right)}$

$x=\frac{2}{3}\pm i\frac{\sqrt{11}}{3}$