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Question

Find the roots of the equation x214x+17=0 by the method of completing the square.

A
x=7±52
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B
x=11±32
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C
x=7±32
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D
x=10±32
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Solution

The correct option is C x=7±32
Given : x214x+17=0

This is same as:
x2[2×(x)×7]+7272+17=0
(x7)249+17=0
(x7)232=0
(x7)2=32
x7=±32
x=7±32

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