CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Find the roots of the following equation.
1x+41x7=1130,x{4,7}

A
1,2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
1,3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
1,3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
1,2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D 1,2
Simplifying, we get
1x+4+1x7=1130
x7x4x23x28=1130
30=x23x28
x23x+2=0
(x1)(x2)=0
x=1 and x=2

flag
Suggest Corrections
thumbs-up
25
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
AM and GM
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon