Find the roots of the following quadratic equation
$2 x^{2} - 7 x + 3 = 0$

\frac{1}{2}, 3

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- \frac{1}{2}, 3

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\frac{1}{2}, - 3

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- \frac{1}{2}, - 3

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Solution

The correct option is A $\frac{1}{2}, 3$
$2 x^{2} - 7 x + 3 = 0$

$\Rightarrow 2 x^{2} - 6 x - x + 3 = 0$

$\Rightarrow 2 x (x - 3) - 1 (x - 3) = 0$

$\Rightarrow (2 x - 1) (x - 3) = 0$

$x = \frac{1}{2}, 3$

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Similar questions

Which of the following is one of the roots of the quadratic equation ${2 x}^{2} - 7 x + 3 = 0$ ?

2 x^{2} - 7 x + 3 = 0

\frac{1}{2}, 3

\frac{1}{2}, - 3

\frac{- 1}{2}, 3

1, \frac{- 1}{2}

2 x^{2} - 7 x + 3 = 0

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