Question

Find the roots of the following quadratic equation by factorisation:
$2x^2+x-6=0$

Answer 1

The roots of the equation is given as $\frac{-1\pm \sqrt{1+48}}{4}$

$=\frac{-1\pm 7}{4}$$x=\frac{6}{4},\frac{-8}{4},=\frac{3}{2},-2$

The given quadratic equation is written as $(x-\frac{3}{2})(x+2)=0$