Question

Find the roots of the following quadratic equation using quadratic formula.

$x^2-2x-8=0$

Answer 1

Consider the given quadratic equation.

$x^2-2x-8=0$

Therefore, using discriminant formula, roots of the equation are,

$x=\frac{2\pm \sqrt{4+32}}{2}$

$x=\frac{2\pm 6}{2}$

$x=-2,x=4$

Hence, these are the required roots of the equation.