Find the roots of the following quadratic equation :
$(x + 3) (x - 1) = 3 (x - \frac{1}{3})$

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Solution

$(x + 3) (x - 1) = 3 (x - \frac{1}{3})$

$x^{2} + 3 x - x - 3 = 3 x - 1$

$\Rightarrow x^{2} - x - 2 = 0$

$\Rightarrow x^{2} - 2 x + x - 2 = 0$

$\Rightarrow (x - 2) (x + 1) = 0$

$\Rightarrow x = 2$ OR $x = - 1$

Hence $- 1$ and $2$ are the roots of given quadratic equation.

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