Question

Find the roots of the following quadratic equations by the factorization method.
$21x^2-2x+\frac{1}{21}=0$

Answer 1

Given equation is $21x^2-2x+\frac{1}{21}=0$
on multiplying by 21 on both side4s, we get
$441x^2–42x+1=0$
441$x^2$ – (21x + 21x) + 1 = 0 [by splitting the middle term]
$\Rightarrow 441x^2$ – 21x – 21x + 1 = 0
$\Rightarrow$ 21x (21x – 1) (21x – 1) = 0
$Now,21x-1=0\Rightarrow x=\frac{1}{21}$
Hence, the roots of the equation 441 $x^2$ – 42x + 1 = 0 are $\frac{1}{21}and\frac{1}{21}$