Question

Find the roots of the following quadratic equations, if they exist, by the method the square:
$4x^2+4\sqrt{3}x+3=0$

Answer 1

$Ans=4x^2+4\sqrt{3}x+3=0$

$(2x{)}^2+2\times 2x\times \sqrt{3}+(\sqrt{3}{)}^2=0$

$(2x+\sqrt{3}{)}^2=0$

$2x+\sqrt{3}=0$

x=$\frac{-\sqrt{3}}{2}$ $\frac{-\sqrt{3}}{2}.$

$\therefore$ this equation has equal

root & equal $\frac{-\sqrt{3}}{2}.$