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Question

Find the roots of the given equation
16x-10x=27


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Solution

Finding the roots of given equation :

Given equation 16x-10x=27
Both sides multiply by x, we get
16x2-10=27x16x2-27x-10=016x2-(32-5)x-10=016x2-32x+5x-10=016x(x-2)+5(x-2)=0(16x+5)(x-2)=0x=-516,2

Hence the required roots are -516&2


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