Question

Find the roots of the quadratic equation $2x^2+3x-5=0$ by using the quadratic formula.

• A. $\frac{-5}{2},-1$
• B. $\frac{5}{2},1$
• C. $\frac{-5}{2},1$
• D. $\frac{5}{2},-1$

Answer 1

The correct option is C $\frac{-5}{2},1$

Given equation is:

$2x^2+3x-5=0$

By using quadratic formula,

$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$\therefore x=\frac{-3\pm \sqrt{3^2-\left(4\right)\left(2\right)(-5)}}{2\left(2\right)}$

$x=\frac{-3\pm \sqrt{9+40}}{4}$

$x=\frac{-3\pm \sqrt{49}}{4}$

$\therefore x=1,x=\frac{-5}{2}$