Find the roots of the quadratic equation 2x2 - 7x + 3 = 0 by the method of completion of squares.
3, 1/2
2x2-7x+3=0
Dividing by the coefficient of x2, we get
x2-72x + 32=0 ; a = 1, b = -72, c = 32
Adding and subtracting the square of b2= -74, (half of coefficient of x)
we get, (x2 - 2(74)x + (74)2) + 32=0
(x−74)2 - 2516 = 0
Taking Square root, (x−74)=(±54)
(x−74)=(54) → x = 3
(x−74)=−(54) → x = 12